Hello Year 6,
Whilst we have another day at home due to maintenance at school, you are required to complete home learning for today and bring it to school tomorrow. The behaviour policy regarding work will still apply if you don’t bring the work to School on Wednesday!
Our Learning Intention for Maths today is:
To identify the relative sizes of two quantities so that I can scale sizes up or down by different amounts
WIN
- To recognise relationships between quantities
- To use multiplication
- To use division
- To know what a scale factor is
- To identify known facts
- To identify unknown facts



You might say 6 is 2 bigger than 4 therefore we need to add 2 lots to the original amount. This is not true.
We need to think about doubling and halving and known facts. Double 4 is 8, 6 is 2 more than 4 and 2 less than 8 therefore we could multiply each quantity by 1/2.
Or we can use our known facts. We know 4 times but we now need to find 6 times. We could divide each quantity by 4 to find what 1 lot is, and then multiply each quantity by 6 to find 6 lots. For example, 20g of butter (4 lots) divided by 4 is 5g (1 lot). We can then multiply our 1 lot (5g) by 6 to find 6 lots. Therefore to make 6 cookies, 5g x 6 = 30g.


My turn:

Known facts: this recipe serves 6 people. Yasmin wants to scale up the recipe to serve 9 people.
There are two strategies I can use.
- I know that 6 and 9 are in the 3 times tables. I can half each amount to find 3 lots (because 6 divided by 2 is 3) and then multiply by 3 (because 3 x 3 = 9). For example: 120g onion halved is 60g. 60g multiplied by 3 (to find 9 lots) is 180g onion.
- I know 6 lots. I can use this to find 1 lot by dividing each amount by 6. For example, 120g onion divided by 6 is 20g. I can then multiply 20g by 9 to find 9 lots. 20g x 9 = 180g onion.
Therefore, each speech bubble demonstrating strategies could be correct because both strategies leads us to the correct scaling.
Your turn:

If you feel confident in this, have a go at scaling the recipe up to serve 30 people.
Further scaling examples:

If I look at the other quantities, these all also have a common factor of 5 and 10. To find the raisins, I can do the same thing. I will divide the original quantity of 20g of raising by 5 which gives me 4g and then I will multiply my 4g by 6 to find my new quantity. 4 x 6 = 24g.
Although all my quantities have a factor of 10, I cannot divide by 10 and then multiply by 6 to get 60 because… 50g divided by 10 is 5g, 5g multiplied by 6 is 30g. I do not reach my new quantity of 60g oats.
Independent task:

Challenge investigation:

Consolidation of learning:
